By the absolute slimmest of margins however. Let me post the z-scores again because we're going to look at this when this season is over: Tannehill z-scores: 2012: -0.8259 2013: -0.3630 2014: 0.3940 2015: -0.1698 2016: 0.3739 2018: -0.0167 So yes 2014 was technically the best but as you can see 2014 and 2016 are essentially identical. They were also the only years he was above average. What is Tannehill's z-score right now? It's a very impressive 1.0474. The average z-score for the entire offense for SB winners is 0.9389 so if Tannehill's current level is his average level this year then that's more than sufficient to build a SB team around. But again.. sample size is small and nothing Tannehill has done so far statistically or otherwise is abnormal for 136 passing attempts. And so it's clear what the statistical test will be at the end of the year, we'll do a 2-sample t-test for unequal samples sizes on his game-by-game ratings after adjusting ratings to a common year and compare his entire career in Miami vs. Tennessee to test whether those two sets of ratings "come from the same QB". We can also do an ANOVA to test whether the adjusted ratings from all years "come from the same QB" (this test separates the data by year). Anyway.. that will show whether you can explain whatever Tannehill does in Tennessee given what he did in Miami by random variation alone, or whether there is something statistically significant with his performance in Tennessee.